ln(x^2-3x+2)/x^2=0

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Solution for ln(x^2-3x+2)/x^2=0 equation: 


D( x )

x^2-(3*x)+2 <= 0

x^2 = 0

x^2-(3*x)+2 <= 0

x^2-(3*x)+2 <= 0

x^2-3*x+2 <= 0

x^2-3*x+2 <= 0

DELTA = (-3)^2-(1*2*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)+3)/(1*2) or x = (3-1^(1/2))/(1*2)

x = 2 or x = 1

a = 1

a > 0

x in <1:2>

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:1) U (2:+oo)

ln(x^2-(3*x)+2)/(x^2) = 0

ln(x^2-3*x+2)/(x^2) = 0

ln(x^2-(3*x)+2)/(x^2) = 0 // * x^2

ln(x^2-(3*x)+2) = 0

ln(x^2-3*x+2) = 0

ln(x^2-3*x+2) = ln(e^0)

x^2-3*x+2 = e^0

x^2-3*x-e^0+2 = 0

x^2-3*x+1 = 0

DELTA = (-3)^2-(1*1*4)

DELTA = 5

DELTA > 0

x = (5^(1/2)+3)/(1*2) or x = (3-5^(1/2))/(1*2)

x = (5^(1/2)+3)/2 or x = (3-5^(1/2))/2

x in { (3-5^(1/2))/2, (5^(1/2)+3)/2 }

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